Tag: frustum

gcse maths volume frustum

r: \[ R^2 = 64, \quad r^2 = 16, \quad Rr= 32 \] \[ R^2 + Rr + r^2 = 64 + 32 + 16 = 112 \] Calculate \( h \): \[ h = \frac{3 \times 150.8}{\pi \times 112} = \frac{452.4}{3.1416 \times 112} \approx \frac{452.4}{351.858}